Comment faire la suite de la factorisation? Merci.

(2a - 3)(a + 5) - 4(a + 5)²
= (a + 5)[2a - 3 - (4(a + 5))]
= (a + 5)(2a - 3 - 4a - 20)
= (a + 5)(- 2a - 23)

(2a-3)(a+5) -4(a+5)²
(a+5) (2a-3 - 4(a+5))
(a+5)(2a-3- 4a -20)
(a+5) (-2a -23)