Mathématiques

Question

Aider moi svp j’ai besoin d’aide
1) Développer puis réduire :
A = 3 (x +2); B = (-7) (6-2t) ; C = 5 (4a - 2); D = Z (22 - 4); E = 7t (5 -2t); F = a (2-a)
G = 5t (4 + 2t); H = 5 (3-2w); I = (-2t) (4 – 5t); J = 7a (9-8a); K = -6 (3 +4a)

1 Réponse

  • Réponse :

    Explications étape par étape :

    A=3 (x +2)

    A=3×x+3×2

    A=3x+6

    B = (-7) (6-2t)

    B = (-7)×6 - (-7)×(2t)

    B = (-42) - (-14t) = (-42) +14t

    C = 5 (4a - 2)

    C = 5 × 4a - 5×2

    C = 20a - 10

    D = Z (22 - 4)

    D = Z × 22 -  Z × 4

    D = 22Z - 4Z

    D = 18Z

    E = 7t (5 -2t)

    E = 7t × 5 - 7t × 2t

    E = 35t - 14t²

    F = a (2-a)

    F = a × 2 - a×a

    F = 2a - a²

    G = 5t (4 + 2t)

    G = 5t × 4 + 5t × 2t

    G = 20t + 10t²

    H = 5 (3-2w)

    H = 5 × 3- 5×2w

    H = 15 - 10w

    I = (-2t) (4 – 5t)

    I = (-2t) × 4 – (-2t) ×5t

    I = (-8t) - (-10t)² = (-8t) + 10t²

    J = 7a (9-8a)

    J = 7a × 9- 7a×8a

    J = 63a - 56a²

    K = -6 (3 +4a)

    K = -6×3 + (-6)×4a

    K = -18 + (-24a) = -18 - 24a

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