Mathématiques

Question

Aidez moi svp
a. 6 + 5 xa=3 xa + 17
b. 11 - a= 2 x (a + 1)
c.3+4x (a - 1) = 5 xa - 7
pour a=5.
pour a = 3.
pour a=6.

1 Réponse

  • Réponse:

    a)

    6+5x × 5 = 3x × 5 +17

    6 +25x = 15x +17

    25x -15x = 17-6

    10x = 11

    10x/10 = 11/10

    x = 11/10

    6+5x × 3 = 3x × 3 +17

    6+15x = 9x +17

    15-9x = 17 -6

    6x = 11

    6x/6 = 11/6

    x = 11/6

    6+5x × 6 = 3x × 6 +17

    6+30x = 18x +17

    30x -18x = 17-6

    12x = 11

    12x/12 = 11/12

    x = 11/12

    b)

    11- 5 = 2x(5+1)

    6 = 10x + 2

    -10x = 2-6

    -10x = -4

    -10x/-10 = -4/-10

    x = 2/5

    11- 3= 2x(3+1)

    8 = 6x + 2x

    8 = 8x

    -8x = -8

    -8x/-8 = -8/-8

    x = 1

    11- 6 = 2x(6+1)

    5 = 12x + 2x

    5 = 14x

    -14x = -5

    -14x/-14 = -5/-14

    x = 5/14

    c)

    3+4x(5-1) = 5x × 5 -7

    3+20x -4x = 25x -7

    20x -4x -25x = -7-3

    -9x = -10

    -9x/-9 = -10/-9

    x = 10/9

    3+4x(3-1) = 5x × 3 -7

    3+12x -4x = 15x -7

    12x -4x -15x = -7-3

    -7x = -10

    -7x/-7 = -10/-7

    x = 10/7

    3+4x(6-1) = 5x × 6 -7

    3+24x -4x = 30x -7

    24x -4x -30x = -7-3

    -10x = -10

    -10x/-10 = -10/-10

    x = 1

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